c++ 类中的char*

Question

假设Student类里有
char* a ="Tom";
char* b ="Rose";

如果有
Student* p;

那么
cout << p->a; // 输出Tom
cout << *(p->a); //输出T

这是为什么呢？ a不是一个指针吗，如果是cout << p->a; 不是应该会输出a的地址吗

为什么cout << *(p->a); 只是输出T呢？

Answer 1

A variable representing a string is essentially a pointer. An expression has two meanings. The compiler must have a certain logic to handle this situation, otherwise it will be a mess

In fact, the implementation logic of the I/O class in the C++ standard library when overloading <<操作符 is: when encountering char类型指针, it will be treated as a string and the character pointed to by the pointer will be output. string.

To output the address, force conversion to 无类型的指针

cout << static_cast<const void *>(p->a);

*(p->a)Why is T

For a char类型指针 value* operation, of course, it is to obtain the value of a char