C++基础问题：指针的引用

Question

C++ primer 第五版的练习题：

Exercise 2.25: Determine the types and values of each of the following variables.
 
(a) int* ip, &r = ip;

请问怎么理解 &r = ip ?

我实在理解不能。。。
r 是一个 int 的引用，如何可以用 ip (一个 int 的指针）赋值呢？

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补充：

正如 @araraloren 在回答中指出的，
这句编译时会报错：

int* ip, &r = ip;

要改成：

int* ip, *&r = ip;

或者

int* ip, &r = *ip;

才可以编译通过。

Answer 1

The type of ip is int*
The type of r is int&
&r = ip; //The compiler will give an error
Maybe the idea of ​​the question is to distinguish the type, and the correctness of the code is second?

Answer 2

&r is the address of r. No one asked to assign int* to r, but to &r, so *(&r)=*ip