c++ - 字符串常量转换问题

Question

#include <iostream>
#include <cstring>

class CTextBlock
{
public:
    CTextBlock(char* tmp)
    {
        pText = tmp;
    }
    char& operator[](std::size_t position) const
    {
        std::cout << "const function" << std::endl;
        return pText[position];
    }
private:
    char* pText;
};

int main()
{
    const CTextBlock cctb("Hello");
    char* pc = &cctb[0];
    *pc = 'J';
    return 0;
}

这个问题怎么解决哦？
我尝试注释掉构造函数中的那一条语句，并把传入参数修改为const类型，编译是可以通过，但是我想的是传入这个字符串并把它赋值给另一个变量，这该怎么解决啊。

Answer 1

If you just don’t see this warning, you can add -Wno-write-strings when compiling.

If you want to organize the code in a reasonable way to avoid warnings, you can use:

char c[] = "Hello";
const CTextBlock cctb(c);

My personal suggestion is to use string.

Answer 2

"Hello"This is a string literal. It is placed in the constant area of ​​the program (the compiler may optimize it away), so passing the address to a char* will naturally cause a warning

Answer 3

Either replace it with const char* or use const_cast.

I also recommend using std::string personally.