c++单例类编译不通过
阿神
阿神 2017-04-17 13:34:10
0
2
903
class Singleton
{
private:
    static Singleton* m_instance;
    Singleton() {}
public:
    static Singleton* getInstance();
};

Singleton* Singleton::getInstance()
{
    if (m_instance==nullptr)
    {
        if (m_instance==nullptr)
        {
            m_instance = new Singleton;
        }
    }
    return m_instance;
}


vs报错:
严重性    代码    说明    项目    文件    行    禁止显示状态

错误 LNK2001 无法解析的外部符号 "private: static class Singleton * Singleton::m_instance" (?m_instance@Singleton@@0PAV1@A) billapp C:\Users\Administrator\Documents\Visual Studio 2015\Projects\billapp\billapp\bill.obj 1
严重性 代码 说明 项目 文件 行 禁止显示状态
错误 LNK2019 无法解析的外部符号 _main,该符号在函数 "int __cdecl invoke_main(void)" (?invoke_main@@YAHXZ) 中被引用 billapp C:\Users\Administrator\Documents\Visual Studio 2015\Projects\billapp\billapp\MSVCRTD.lib(exe_main.obj) 1


为什么会不通过?
阿神
阿神

闭关修行中......

reply all(2)
大家讲道理

You need to add a sentence
Singleton * Singleton::m_instance = 0;
otherwise there will be a link error

阿神

The error may be related to the declaration of static members.

In addition, the singleton pattern can be implemented using references to local static variables. Reference here.

class S
{
    public:
        static S& getInstance()
        {
            static S    instance; // Guaranteed to be destroyed.
                                  // Instantiated on first use.
            return instance;
        }
    private:
        S() {}                    // Constructor (the {} brackets) are needed here.

        // C++ 03
        // ========
        // Dont forget to declare these two. You want to make sure they
        // are unacceptable otherwise you may accidentally get copies of
        // your singleton appearing.
        S(S const&);              // Don't Implement
        void operator=(S const&); // Don't implement

        // C++ 11
        // =======
        // We can use the better technique of deleting the methods
        // we don't want.
    public:
        S(S const&)               = delete;
        void operator=(S const&)  = delete;

        // Note: Scott Meyers mentions in his Effective Modern
        //       C++ book, that deleted functions should generally
        //       be public as it results in better error messages
        //       due to the compilers behavior to check accessibility
        //       before deleted status
};
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