java - 怎么用脚本判断几个连续的中文字符是一个姓名？？

Question

冷狐毕军,
高李阳子,
闻人共建,
欧阳新成,
徐姜敏然,
某家公司,
欧阳伟强,
石戴菲子,
朱为准,
徐海峰,
王潇荔,
种亚男,
付义平,
鲁雅萍,
... ...

如上面的例子，怎么用脚本判断他们是一个名字，不是的自动删除所在行！
不限定语言！
我的想法是，把百家姓写入一个文件中，取要识别的中文字符串的第一个字，去匹配百家姓每个姓的第一个字，如果有匹配的，第二步，反过来取这个姓的完整中文字符串，假设这个姓中文字符长度为n，拿去匹配那个要识别的中文串的前n个字符，如果也匹配，默认它就是一个中文姓名！
难实现吗？

Answer 1

The surname is easy to handle. The key is how to judge the first name. The logic is more troublesome, but the implementation is very simple. . . .
In addition, surnames not only have one character, but also have compound surnames. .

Answer 2

Can’t tell.
I can name my son
"How to use", "script judgment", "break a few", "continuous", "continuous", "Chinese characters"... are completely in compliance with Chinese law.

Answer 3

You need Named Entity Recognizer (NER)
For example: http://nlp.stanford.edu/software/CRF-NER.shtml Although it says "Chinese models built from the Ontonotes Chinese named entity data", the effect is not confirmed