c++ - 为什么main函数里调用函数不能加类型？

Question

如果加了就会出现
[Warning] parameter names (without types) in function declaration [enabled by default]

Answer 1

The compiler interprets your line as a function declaration, so it prompts you: type without parameters (without types)
For example:
int main(int argc, char *argv[] )
{

int main(argc, argv);
return 0;

}
will prompt line 3 [Warning] parameter names (without types) in function declaration [enabled by default]
int main(int argc, char *argv[])
{

int main(int argc, char *argv[]);
return 0;

}
declares no ambiguity and no warning.

Answer 2

There is no need to write the return value type when calling a function, just write the function name and parameters directly

Answer 3

I’m also confused, there’s a word limit on answering questions

Answer 4

Because the call itself does not add a type, adding a type is a declaration.