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This can be matched grep -o "ed2k[^"]*"
grep -o "ed2k[^"]*"
[root@localhost oldlog.md]# echo '你的地址' | grep -o "ed2k[^\"]*" ed2k://|file|%E7%A1%85%E8%B0%B7.Silicon.Valley.S01E01.%E4%B8%AD%E8%8B%B1%E5%AD%97%E5%B9%95.HDTVrip.1024X576.mkv|348759100|04dc44e4978ea2d4dc9bf41b08829a3e|h=rfe5smulijxlmz7mgtpmn2bt3vmofk56|/ ed2k://|file|silicon.valley.s01e01.720p.hdtv.x264-killers.mkv|843706966|3B4B08BD9C960B5B8F2372158F84B1AE|h=36632AROF43T63NSXFLIGSYEB4PNDEFN|/
It is recommended to use some HTML parser to extract the a tag separately for matching, which can avoid the problem of multiple a's in one line
By default grep doesn't support non-greedy modifiers, but you can use grep -P to use the Perl syntax.
How to do a non-greedy match in grep?
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This can be matched
grep -o "ed2k[^"]*"It is recommended to use some HTML parser to extract the a tag separately for matching, which can avoid the problem of multiple a's in one line
By default grep doesn't support non-greedy modifiers, but you can use grep -P to use the Perl syntax.
How to do a non-greedy match in grep?