mysql - 查询每小时内的生成订单数超过十条的用户

Question

有一个order的表，字段有orderID，username，create_time。如何查询出异常用户及其异常订单？

异常用户的判定：同一用户，每一小时内下单超过十个则为异常用户

注：是每个小时的噢，一个24个小时，然后一年365天，都要查出来，只有用户有一次一小时内充值下单超过十次就算异常，要查出所有异常单和异常用户

Answer 1

You can use mysql's group by username to perform classification and aggregation, count the summary results (orderID), and limit the create_time to within 1 hour. I don't know what field you use for create_time, whether it is an unsigned integer or a date. Time type, their definition methods are different, please search by yourself.

Answer 2

select *
from order AS o
where o.create_time > DATE_SUB(now(),INTERVAL 10 MINUTE)