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关于boolalpha,我知道它可以将布尔类型以true或者false输出。例如 :
bool x = ture; cout << boolalpha << x << endl;
那么会输出true;然而在xcode输出时会联想到这个函数
boolalpha(<#std::ios_base &__str#>)
这个是什么意思呢?
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std::boolalpha itself is a function, call ios_base::setf
std::boolalpha
ios_base::setf
streamReloadoperator<< (std::ios_base& (*func)(std::ios_base&)).
stream
operator<< (std::ios_base& (*func)(std::ios_base&))
If it is not made into a function, it needs to be written like this, because setf returns fmtflags, not stream
fmtflags
cout.setf(ios_base::boolalpha); cout << x << endl;
std::boolalpha
itself is a function, callios_base::setf
stream
Reloadoperator<< (std::ios_base& (*func)(std::ios_base&))
.If it is not made into a function, it needs to be written like this, because setf returns
fmtflags
, notstream