node.js - sequelize查询语句时转成的MYSQL语句中表名并不是自己定义的?

Question

我在查询数据库时，定义的模板是：

module.exports = function(sequelize,Sequelize){

var User = sequelize.define('userinfo',{
            id:{
                type: Sequelize.FLOAT,
                primaryKey: true
            },
            name:{
                type:Sequelize.STRING
            } ,
            password :{
                type: Sequelize.STRING
            },
            email :{
                type: Sequelize.STRING
            } ,
            phone :{
                type: Sequelize.STRING
            },
            qq :{
                type: Sequelize.STRING
            },
            ifmanager:{
                type: Sequelize.BOOLEAN
            }
        });
return User;

}

然后进行调用：
var User = require('./module/userinfo')(sequelize,Sequelize);

var result = yield User.findAll({
    attributes:['password'],
    where:{
        name:name
    }
});
console.log(result);

但最终控制台打印出的MYSQL语句是
SELECT password FROM userinfos AS userinfos WHERE userinfos.name = 'jession'
请问userinfos是怎么来的？

Answer 1

In fact, the real table name can be set in the defined model. The third parameter of sequelize.define is a json object, in which the tableName can be set. For specific usage, please refer to the official sequelize documentation