linux - find 命令使用posix-egrep, 不好使
ringa_lee
ringa_lee 2017-04-17 16:19:50
0
1
712

2016/12/8

问题

根据我的了解, find中一般使用shell通配符, 但是shell通配符的表达能力不是很强, 所以就想使用正则, 但是结果不如人意.

查阅了文档, 自认为是按照文档的描述做的, 不知问题出在何处.

相关代码

  • 定制的find命令

find-regex() {
    # find-regex $path $pattern
    if [ $# = 0 ]; then                                                                                     
        echo "Usage: find-regex $path $pattern"
    else
        find "$1" -regextype posix-egrep -regex "$2"
    fi  
}
  • man find

 -regextype type
              Changes the regular expression syntax understood by -regex and -iregex  tests  which  occur
              later  on  the  command line.  Currently-implemented types are emacs (this is the default),
              posix-awk, posix-basic, posix-egrep and posix-extended.
ringa_lee
ringa_lee

ringa_lee

reply all(1)
左手右手慢动作

There is no problem with the usage. The reason why you don't get the result you want may be because "" the special characters in $2 contained in double quotes may be interpreted by the shell.

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