python - numpy使用中的一个错误
阿神
阿神 2017-04-17 17:33:52
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import numpy as np
import matplotlib.pyplot as plt
from math import pow
from math import e

def main(x):
    dishu = e
    zhishu = 1/e
    result = zhishu
    cishu = x
    while cishu > 1:
        result = pow(zhishu, result)
        cishu -= 1
    main_result = pow(dishu, result)
    return main_result
    

x = np.linspace(2, 100, 90)
y = main(x)

这段代码在运行时抛出的一段错误是:
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
我在stackoverflow上面也搜过同样的错误信息,但我不明白是这里为什么有多种返回的可能性,这个问题究竟该如何解决?

我试着用for去一个个的得到结果,但这回到了matplotlib报错:

ValueError: x and y must have same first dimension

请问该怎样写才能将main这个函数的图像在matplotlib里面呈现?

阿神
阿神

闭关修行中......

reply all(2)
阿神

x is a list, cishu=x, cishu > 1. What does it mean? A list greater than 1?

巴扎黑

while cishu > 1:
There are 2 steps here

1) 先计算 cishu > 2,得到一个临时变量
2)  对于1)得到的临时变量, 用while计算其boolean值,为False时返回

cishu > 1 The result calculated here is a numpy.ndarray, which cannot be calculated with boolean

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