python - 如何让列表所有元素首字母变大写？

Question

希望列表 c 所有元素首字母变大写，这样写为甚么会出错？该如何写？

c=['zz','yy','xx'] 
c[0:2]=c[0:2].capitalize()

# 提示错误
AttributeError: 'list' object has no attribute 'capitalize'

Answer 1

capitalize is a string method, and c[0:2] is a list, so when you call capitalize Something went wrong. capitalize 是字串的方法，而 c[0:2] 是一個 list，所以你調用 captitalize 的時候會出錯．

c = ['zz','yy','xx'] 
c = [string.capitalize() for string in c]

還有這樣也可以:

c = ['xx', 'yy', 'zz']
c = ' '.join(c).title().split()

P.S. 在使用 list 的時候，如果要操作的是整個串列，那不需要特別使用到切片，c[0:2] 在這裡是個不必要的做法．

給你參考！

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@moling3650， 使用 title 真的是個有趣的主意，capitalize 只會將字串的首字大寫，而 title

>>> string = 'my name is dokelung'
>>> string.capitalize()
'My name is dokelung'
>>> string.title()
'My Name Is Dokelung'

You can also do this:

>>> c = ['xx', 'yy', 'zz']
>>> ' '.join(c).title().split()
['Xx', 'Yy', 'Zz']

P.S. When using list, if you want to operate the entire list, there is no need to use slicing. c[0:2] is unnecessary here.

For your reference!

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@moling3650, Using title is really an interesting idea. capitalize will only capitalize the first word of the string, while title The first character of all #🎜🎜# words #🎜🎜# in the string will be capitalized. #🎜🎜# #🎜🎜# See example: #🎜🎜# rrreee #🎜🎜#So this is okay: #🎜🎜# rrreee

Answer 2

[_.capitalize() for _ in c]

Answer 3

Write something different

c = [_.title() for _ in c]

Answer 4

The list object has no capitalize method

Answer 5

Write something different

map(str.title, c[0:2])