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我们知道re.findall()可以匹配所有不重叠的匹配成功的部分,那如何进行可重叠的匹配呢?求大神不吝赐教。
举一个例子
假设text = "acbca",pattern = "(a.*b)|(b.*a)"使用re.findall(pattern, text)结果是这样的: [("acb", "")]"bca"这一个片段并不会被找到。问题就是,如何让"acb"和"bca"两个片段都能被匹配上呢?
text = "acbca"
pattern = "(a.*b)|(b.*a)"
re.findall(pattern, text)
[("acb", "")]
"bca"
"acb"
闭关修行中......
key = "gost.default.api.access.user.kicktype.limitusers.count@"p1 = ".((api).access)."pattern1 = re.compile(p1)matcher1 = re .search(pattern1,key)matcher1.group(0)matcher1.group(1)matcher1.group(2)Use () to save the capture group
key = "gost.default.api.access.user.kicktype.limitusers.count@"
p1 = ".((api).access)."
pattern1 = re.compile(p1)
matcher1 = re .search(pattern1,key)
matcher1.group(0)
matcher1.group(1)
matcher1.group(2)
Use () to save the capture group