android - 关于RxBus的一个疑问...

Question

1 . 先上我写的一个方法：

public static Observable<RxEvent> sendBytesRx(ByteBuffer buffer) {
        writeThread.add(buffer);
        return RxBus.getDefault().toObserverable(RxEvent.class);
}

这是一个发送数据到服务器的一个函数。

---

2 . 然后我就调用：

@OnClick(R.id.button2)
    public void btn2(Button button) {
        BgService.sendBytesRx(CSAPIUtils._1_LogIn(xxx,xxx))
                .observeOn(Schedulers.newThread())
                .compose(this.bindUntilEvent(ActivityEvent.DESTROY))
                .subscribeOn(Schedulers.newThread())
                .subscribe(
                        rxEvent -> {
                            //解析数据
                            LogUtils.e(OpenLog,TAG,"1");
                        },throwable -> {
                            LogUtils.e(OpenLog,TAG,throwable.getMessage());
                        });
    }

3 . 发现有点不对，
当我多次点击这个Button，触发OnClick方法，发现，
第一次点击，返回数据，打印：1
第二次点击，返回数据，打印：1 1
...
好像是每次点击的时候，就订阅了这个RxBus的事件，但是
事件完成之后却没有去取消订阅...

请教各位大神！刚入Rx大门。

Answer 1

Subscribe multiple times and each subscriber will receive the message.
Solution: Only subscribe once during onCreate, or cancel the current subscription after receiving the message

Answer 2

There shouldn’t be any big problems with the second paragraph of code, except for the specification of Schedulers. The main problem lies in the first paragraph. Let’s take a look at the first paragraph of code:

public static Observable<RxEvent> sendBytesRx(ByteBuffer buffer) {
        writeThread.add(buffer);
        return RxBus.getDefault().toObserverable(RxEvent.class);
}

RxBus.getDefault().toObserverable(RxEvent.class) This should be the problem, it depends on the specific implementation code.

p.s. It has nothing to do with the subscription timing. If it does, it is a problem with your own code logic. Rx subscription can be done at any time.