android - Error: java.lang.IndexOutOfBoundsException: Invalid index 2
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PHP中文网 2017-04-17 18:01:43
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How to remove the seperator line in footerLayout? I have a footerLayout below the listView, used to display the totalAmount as shown below. If I click the seperator line in footerLayout, my app crashed.

My MainActivity

AllAdapter obj = new AllAdapter(getApplication(), search, listview,imageView,text,button);
footerLayout = (LinearLayout) getLayoutInflater().inflate(R.layout.under_listview, null);
totalAmount = (TextView) footerLayout.findViewById(R.id.amount);

LogCat error

 java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2
            at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
            at java.util.ArrayList.get(ArrayList.java:304)
            at com.example.tony.monthlyexpenses.adapter.AllAdapter.getItem(AllAdapter.java:61)
            at com.example.tony.monthlyexpenses.QuickExpenses$1.onItemClick(QuickExpenses.java:88)
            at android.widget.AdapterView.performItemClick(AdapterView.java:301)

The error pointed to listView onClickListener

 listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                mClickedPosition = position;
                Expenses o = (Expenses) obj.getItem(position);
                String day = o.getDate();
            }
        });

AllAdapter

 public Expenses getItem(int position) {
        return search.get(position);
    }

The footerLayout is supposed to be displayed outside the listView, not inside. How can I get rid of this ?

I also have activity_main.xml, AllAdapter class, all_adapter.xml for ListView and also under_listview.xml for the footerLayout.

activity_main

AllAdapter

under_listview

How to move the footerLayout out from the ListView ?

I add android:footerpidersEnabled="false" now become like this

But still clickable !!!

谁知道问题出在哪?

footerLayout被按时如何不出现灰色?

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reply all(4)
左手右手慢动作

It’s a very simple but error-prone problem. Added footer后,你的listview item数量是3,但adapterviewcount其实并没有变成3,所以在你点击footer时执行的是obj.getItem(2),肯定是数组越界异常了。对于添加了header或footer的listview, the correct way to get the item should be

listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                Expenses o = (Expenses) listView.getAdapter().getItem(position);
                if(o != null){
                    mClickedPosition = position;
                    //Expenses o = (Expenses) obj.getItem(position);
                    String day = o.getDate();
                }
            }
        });

header或footer属于AdapterView的子viewlistView.getAdapter().getItem(position);It can ensure that you do not cross the boundary when taking the position of 2, and then make an object null judgment.

Peter_Zhu

You cannot use setOnItemClickListener as the click event of footview. I think you should set it separately
For example, footview.setonClickListener(new OnClickListener{}); Good luck to you

伊谢尔伦

Your array subscript is out of bounds. Your array size is 2, so the corresponding subscripts can only be 0 and 1, but you used 2 when using it. The error shows that you have an invalid index 2. Look for lines 61 and 88 yourself to see if there is any place where the index is 2 is called

伊谢尔伦

The way to write footerLayout移出listView is

listview.addFooterView(footerLayout, null, false);

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