gevent-socketio - Python gevent和Queue的问题

Question

访问6个URL，怎么样才能开启两个gevent，当访问结束后，继续访问剩下的4个URL。
下面这段代码，访问两个URL后程序就结束了。

代码

# coding=utf-8

from gevent import monkey; monkey.patch_socket()
import gevent
import requests
import queue

q = queue.Queue()

def get_data(url):
    print('GET: %s' %url)
    resp = requests.get(url)
    data = resp.text
    print('%d bytes received from %s.' %(len(data), url))

q.put('http://www.baidu.com')
q.put('http://www.163.com')
q.put('http://www.sougou.com')
q.put('http://www.bing.com')
q.put('http://www.tudou.com')
q.put('http://www.v2ex.com')

gevent_list = []

for i in range(2):
    gevent_list.append(
        gevent.spawn(get_data, q.get_nowait())
    )

gevent.joinall(gevent_list)

Answer 1

I solved it myself, I should get it from the queue in the get_data method

def get_data():
    while not q.empty():
        url = q.get_nowait()
        print('GET: %s' %url)
        resp = requests.get(url)
        data = resp.text
        print('%d bytes received from %s.' %(len(data), url))

There is no need to pass parameters when spawning below.