python - 怎么取出排序后字典中的第一个键值对

Question

一个空字典d=dict(),向其中添加多对元素，对其进行排序后如何取出第一个键值对（相当于索引为0的）。
也即若排序后d={"a":1,"b":2,"c":3,"d":4}（但是我们并不知道其中元素是什么），如何取出第一个键值对，也即（"a":1），不要把所有的都打印出来。谢谢！

Answer 1

sorted(d.items())[0]

Answer 2

d = {"a":1,"b":2,"c":3,"d":4}

k = d.keys()[0]
print k, d[k]

Answer 3

>>> d={"a":3,"b":1,"c":5,"d":2}
>>> sorted(d.items())
[('a', 3), ('b', 1), ('c', 5), ('d', 2)]
>>> max(zip(d.values(),d.keys()))
(5, 'c')
>>> min(zip(d.values(),d.keys()))
(1, 'b')
>>> sorted(zip(d.values(),d.keys()))[0]
(1, 'b')
>>> 

sorted(d.items()) is sorted by key. If you want to sort by value, you can use the above method.