java - @query注解怎么获取方法参数的某个属性值
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PHPz 2017-04-18 10:13:13
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@Query("select h from Hotel h where h.city = ?1")
List<Hotel> queryWorkFormList(City city);
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Example given by Spring:

@Query("select u from User u where u.firstname = :#{#customer.firstname}")
List<User> findUsersByCustomersFirstname(@Param("customer") Customer customer);
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