python字符串用十六进制表示

Question

我想将输入的字符串用十六进制表示，首先声明，并不是转换成十六进制的字符串，而是像下面的反过程：

>>> '\x61\x62\x63\x64'
'abcd'

我尝试了python3中的encode('UTF-8')等方法，但是都没有找到怎样可以达到我的目的，Python中是否能够完成这个功能，如果可以，怎样才能达到我的目的，希望各位大神能够指教。

Answer 1

>>> '\x61\x62\x63\x64' == 'abcd'
True

There is no way to print out 'x61x62x63x64'. If you just want to check the ascii value corresponding to 'a', you can use ord()

>>> ord('a')
97
>>> chr(97)
'a'

I don’t know if this can meet your requirements

>>> [hex(ord(x)) for x in 'abcd']
['0x61', '0x62', '0x63', '0x64']

Answer 2

python3

>>> print(''.join((r'\x%2x'%ord(c)for c in 'abcd')))
\x61\x62\x63\x64
>>> print(''.join((r'\x%2x'%c for c in bytes('abcd','l1'))))
\x61\x62\x63\x64
>>> print(''.join((r'\x%2x'%c for c in b'abcd')))
\x61\x62\x63\x64

Answer 3

There are several functions in the binascii library that can do this

import binascii
print(binascii.b2a_hex(b'abcd'))
# b'61626364'

Or write directly like this in py3.5

print(b'abcd'.hex())
# 61626364