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python中怎么对列表以区间进行统计?假设list=[1,1,1,2,3,4,4,5,5,6,7,7,7,7,8,9,9,9,10……99,99,99,100,100]
怎么写程序可以以10为一个区间分别统计,如统计出小于10的数字频率,大于10小于20的频率,大于20小于30的频率……大于90小于100的频率?抱歉题目描述的不好
闭关修行中......
# code for python3 from itertools import groupby lst = [1, 1, 1, 2, 3, 4, 4, 5, 5, 6, 7, 7, 7, 7, 8, 9, 9, 9, 10, 99, 99, 99, 100, 100] dic = {} for k, g in groupby(lst, key=lambda x: (x-1)//10): dic['{}-{}'.format(k*10+1, (k+1)*10)] = len(list(g)) print(dic)
Result:
{'91-100': 5, '1-10': 19}
Questions I answered: Python-QA
# coding: utf-8 lst = [1, 1, 1, 2, 3, 4, 4, 5, 5, 6, 7, 7, 7, 7, 8, 9, 9, 9, 10, 99, 99, 99, 100, 100] intervals = {'{0}-{1}'.format(10 * x + 1, 10 * (x + 1)): 0 for x in range(10)} for _ in lst: for interval in intervals: start, end = tuple(interval.split('-')) if int(start) <= _ <= int(end): intervals[interval] += 1 print intervals
Result:
Questions I answered: Python-QA