socket编程 - python如何进行socket连接

Question

尝试连接 119.23.124.81:7575

服务器每5秒会返回一个{"type":"ping"}，我尝试用以下代码去连接，但是无法获取到这个{"type":"ping"}:

s = socket(AF_INET, SOCK_STREAM)
# 建立连接:

s.connect(('119.23.124.81', 7575))
while True:
    print(s.recv(1024).decode('utf-8'))

s.close()

代码不会报错，但是也获取到我想要的内容

请问要如何写才能获取到这个{"type":"ping"}

---

Answer 1

I figured it out, it turns out this is the websocket protocol used, not an ordinary socket

Just use the websocket library instead. The code is as follows:

from websocket import create_connection


ws = create_connection("ws://42.96.131.185:7575")
print("Sending 'Hello, World'...")
for i in range(10000):
    ws.send(b"Hello, World")
    print("Sent")
print("Reeiving...")
result = ws.recv()
print("Received '%s'" % result)
ws.close()

Answer 2

Refer to official documentation

# Echo server program
import socket

HOST = ''                 # Symbolic name meaning all available interfaces
PORT = 50007              # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
    data = conn.recv(1024)
    if not data: break
conn.sendall(data)
conn.close()

and

import SocketServer

class MyTCPHandler(SocketServer.BaseRequestHandler):
"""
The request handler class for our server.

It is instantiated once per connection to the server, and must
override the handle() method to implement communication to the
client.
"""

    def handle(self):
        # self.request is the TCP socket connected to the client
        self.data = self.request.recv(1024).strip()
        print "{} wrote:".format(self.client_address[0])
        print self.data
        # just send back the same data, but upper-cased
        self.request.sendall(self.data.upper())

if __name__ == "__main__":
    HOST, PORT = "localhost", 9999

    # Create the server, binding to localhost on port 9999
    server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)

    # Activate the server; this will keep running until you
    # interrupt the program with Ctrl-C
    server.serve_forever()

Answer 3

Because the data you send is a dictionary object, when sending data through the socket, use the pickle or json module to serialize the data before sending it. Correspondingly, the receiving end must use pickle or json for deserialization.