网页爬虫 - python爬虫翻页问题,请问各位大神我这段代码怎样翻页,还有价格要登陆后才能看到,应该怎么解决
黄舟
黄舟 2017-04-18 10:32:00
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import urllib.request
import re
web=urllib.request.urlopen('https://www.gpyh.com/pricebuy/index?pageNum=1&hasStock=&goodsStandardId=1931&materialDictCode=&materialGroupCode=037001&diameter=&length=&brandId=&merchantId=')
neirong=web.read()
def getPage(self,pageIndex):
    url = self.siteURL + "?pageNum=" + str(pageIndex)
    request = urllib2.Request(url)
    response = urllib2.urlopen(request)
    return response.read().decode('gbk')
jiangrenhua=neirong.decode('UTF-8')
RegularExpression='<td>(.*)<\/td>'
Valuable=re.findall(RegularExpression,jiangrenhua)
information=[]
for i in range(173):
    print(Valuable[i]
黄舟
黄舟

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黄舟
?pageNum=" + str(pageIndex)

Isn’t this your page number control?
If you see it after logging in, use cookies or username and password to simulate logging in and get it

迷茫

httplib2 should basically be the terminator of all http requests.

import httplib2
import urllib
http = httplib2.Http()
url='要获取的地址'
header={'Accept':'text/html',
     'Accept-Encoding':'gzip, deflate, sdch',
     'Accept-Language':'zh-CN,zh;q=0.8',
     'Cache-Control':'max-age=0',
     'Connection':'keep-alive',
     'Cookie':'cookie内容',
     'Upgrade-Insecure-Requests':'1',
     'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/45.0.2454.101 Safari/537.36'}   #要有登陆状态才能翻页就要模拟登陆后把cookie放进去
body_value={'username':'test','password':'123456'} #表单的所有内容
body_value=urllib.urlencode(body_value) #utf8编码
response, content = http.request(url, 'GET', headers=header,body=body_value)  #GET或者POST方法
response.encoding = 'utf-8'
#content就是返回内容
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