java - Jpa返回对象必须是与Entity类么?
迷茫
迷茫 2017-04-18 10:56:32
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  @Query(value = "SELECT id as topicId,content FROM bbs_topic WHERE create_time BETWEEN ?1 AND ?2",nativeQuery = true)
    List<IndexObject> getBbsTopicListByDate(Date fileupdateDate, Date topiclastupdate);

其中IndexObject 是显示层vo。
然后报错

org.springframework.core.convert.ConversionFailedException: Failed to convert from type [java.lang.Object[]] to type [com.wayne.common.lucene.entity.IndexObject] for value '{59, 再发表一次看看那}'; nested exception is org.springframework.core.convert.ConverterNotFoundException: No converter found capable of converting from type [java.lang.Integer] to type [com.wayne.common.lucene.entity.IndexObject]

度娘了一下
怀疑 jpa返回对象必须是与Entity类相关(Entity就是配置了Java类与数据库映射的Java类)
有大神知道对么?

迷茫
迷茫

业精于勤,荒于嬉;行成于思,毁于随。

reply all(1)
伊谢尔伦

The error you reported here is that the query statement returned an Object[] array. Jpa tried to convert it into your custom object, but failed. You can try the following method:

  1. Use the syntax of select new + the full class name of the object,
    Here Perso is the entity managed by EntityManager, and PersonResult is the custom entity

    @Query(select new com.xx.yy.PersonResult(p.id,p.name,p.age) from Person p)
     List<PersonResult> findPersonResult();
  2. Use Object[] array to receive data. Each element value in Object[] is the value of the corresponding column

    @Query(select p.id,p.name,p.age from Person p)
     List<Object[]> findPersonResult();
  3. First find Person and convert it into PersonResult using java code

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