objective-c - 给一个json体, 根据字段自动生成 一个model类出来 哪个大神知道这是怎么回事

Question

我的意思是 给一个json , 它能给我建个类, 类里面直接匹配好属性.是第三方还是有方法 请大神指教

Answer 1

The following reference
MJExtension
JSONModel

You can also process Json yourself, convert json into a dictionary, and then use the dictionary to assign values ​​to the properties of the object (traverse the properties of the object and assign values)

Answer 2

As Blake said, first convert Json into a dictionary, and then convert the dictionary into a model. Regarding dictionary conversion, I just wrote an article a few days ago on the underlying principles of how the MJExtension framework converts a dictionary into a model. You can take a look at it. http: //weibo.com/p/1001603912111561547915
Because it is mainly implemented through Runtime, you need to understand the basics of Runtime first

Answer 3

https://github.com/EnjoySR/ESJsonFormat-Xcode You can try this

Answer 4

To convert json into classes, you need to consider the following two issues
1. How to generate beautiful class types
2. What to do if the shape of each map in the array is different (usually it may mean inheritance

However, the second point is the knowledge implicit in the semantics that is difficult to obtain from a json.

Answer 5

I estimate that most people use third parties

Answer 6

There is an Xcode plug-in that can achieve similar functions, called ESJsonFormat ● GitHub address
It can automatically create classes and attributes based on the content of JSON strings.
For details, please see the DEMO in GitHub.

Answer 7

xcode uses ESJsonFormat and IDEA uses GsonFormat.