angular.js - 如何从$scope中的对象属性中找到父节点

Question

例如：
$scope.a=
{

a:{a1:1,a2:2,a3:3},
b:{b1:1,b2:2,b3:3},

}
函数从参数中取得了a3,怎样向上访问取到$scope.a

Answer 1

This is not possible, attributes are not unique.

$scope.a = {
    a: {a1:1, a2:2, a3:3}
    b: {a1:1, a2:2, a3:3}
}

$scope.b = {
    a: {a1:1, a2:2, a3:3}
    b: {a1:1, a2:2, a3:3}
}

So for the above code, what can we get with a3=3?