js實作頁面轉送功能範例程式碼_javascript技巧

以下是範例圖:
 
以下是程式碼:

複製程式碼 程式碼

function forward()
{
//對發送內容拼接字串,整理之後發送.
var temp = "";
var array = new Array();
$("#yxdwlb tr").each(function(){
var flag = false;
var user = "";
$(this).find("td"). each(function(n){
if(n == 0){
//user = user $(this).find("input").is(":checked") "," ;
flag = $(this).find("input").is(":checked");
}
if(n == 1){ user = user this.innerText ",";}
if(n == 2){ user = user $(this).find("input").val() ",";}
if(n == 3){ user = user $( this).find("input").is(":checked") ",";}
if(n == 4){ user = user $(this).find("input").is( ":checked") ";";}
});//欄位
if(flag == true){
array.push(user);
}
}); //行
for(var i = 0 ;i{
temp = temp array[i];//把陣列的原素拼裝成字串存入temp變數,
}
$("#array").val(temp);//temp變數存入參數array
//description不為空的判斷
var description=jQuery(" #description").val();
if(trim(description)=='') {
triman.alert("請輸入描述內容!");
return;
}
//取得表單內容並轉送
var doc = document.getElementById("document");
doc.action = "${pageContext.request.contextPath}/documentManager/save";
docdoc .method = "post";
doc.submit();
}