Original Question: How to determine if an array contains only integers?
Native PHP Solution:
The array function provides a more concise method to achieve this:
<code class="php">$only_integers === array_filter($only_integers, 'is_int'); // true $letters_and_numbers === array_filter($letters_and_numbers, 'is_int'); // false</code>
This approach utilizes the array_filter() function to create a new array containing only elements that satisfy the is_int() condition. By comparing the original and filtered arrays, we can determine if the original array contained only integers.
Higher-Order Function Helpers:
To enhance flexibility, consider defining helper functions:
<code class="php">function all($elems, $predicate) {
return !any($elems, $predicate); // true if all validate
}
function any($elems, $predicate) {
foreach ($elems as $elem) {
if (call_user_func($predicate, $elem)) {
return true; // true if any validate
}
}
return false;
}</code>Now, you can use these functions for more complex scenarios:
<code class="php">all([1, 2, 3], 'is_int'); // true any([1, 'a', 'b'], 'is_int'); // true</code>
This solution provides a concise and flexible way to verify integer arrays in PHP, catering to various use cases.
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