如何在 PHP 中有效驗證純整數數組？

Verifying Integer-Only Arrays with PHP

One way to check if an array exclusively contains integers is through manual iteration and the is_int() function. However, a more efficient approach utilizes native PHP functionality:

Using array_filter()

array_filter() maintains elements of an array that meet a specified condition. Applying it with is_int() as the predicate directly yields a filtered array:

<code class="php">$only_integers = array_filter($only_integers, 'is_int'); // true
$letters_and_numbers = array_filter($letters_and_numbers, 'is_int'); // false</code>

Employing Reusable Helper Functions

This approach can be augmented with reusable helper functions:

<code class="php">/**
 * Verify all elements of an array satisfy a given predicate.
 *
 * @param array $elems Array to evaluate
 * @param callable $predicate Predicate to apply
 * @return bool TRUE if all elements pass, FALSE otherwise
 */
function all($elems, $predicate) {
  foreach ($elems as $elem) {
    if (!call_user_func($predicate, $elem)) {
      return false;
    }
  }

  return true;
}

/**
 * Verify any element of an array satisfies a given predicate.
 *
 * @param array $elems Array to evaluate
 * @param callable $predicate Predicate to apply
 * @return bool TRUE if any element passes, FALSE otherwise
 */
function any($elems, $predicate) {
  foreach ($elems as $elem) {
    if (call_user_func($predicate, $elem)) {
      return true;
    }
  }

  return false;
}</code>

By employing these helper functions, the original code can be simplified:

<code class="php">$has_only_ints = all($only_integers, 'is_int'); // true
$has_only_ints = all($letters_and_numbers, 'is_int'); // false</code>

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