如何解決 Python 處理 CSV 檔案時出現的「FileNotFoundError: [Errno 2] No Such File or Directory」錯誤？

Handling "FileNotFoundError: [Errno 2] No Such File or Directory" in Python

When attempting to access a CSV file in Python, you might encounter the "FileNotFoundError: [Errno 2] No such file or directory" error. This error indicates that the specified file cannot be located by the Python interpreter.

To resolve this issue, it is essential to verify that the file exists in the expected location. By default, Python searches for files in the current working directory. You can confirm the current working directory using os.getcwd(), as demonstrated below:

<code class="python">import os

cwd = os.getcwd()
print("Current working directory:", cwd)</code>

If the file is not located in the current working directory, you can either move it there or specify an absolute path to the file when opening it. An absolute path provides the complete location of the file on the file system, starting from the root directory. For example:

<code class="python">f = open("/Users/foo/Desktop/address.csv")</code>

Alternatively, you can use the os.path.join() function to construct a relative path from the current working directory to the file location. This is useful when the file is in a subdirectory of the current working directory.

<code class="python">import os

path = os.path.join(cwd, "data", "address.csv")
f = open(path)</code>

By ensuring that the file is accessible in the specified location, you can prevent the "FileNotFoundError" and successfully open and process the CSV file.

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