即使特定月份不存在數據,如何在 MySQL 中檢索按月記錄?

Susan Sarandon
發布: 2024-11-07 15:39:02
原創
744 人瀏覽過

How to retrieve month-wise records in MySQL even if no data exists for specific months?

即使資料不存在,如何在MySQL 中選擇按月記錄

從使用者表中擷取按月記錄,您可以使用如下查詢:

SELECT COUNT(`userID`) AS total, DATE_FORMAT(`userRegistredDate`, '%b') AS MONTH, YEAR(`userRegistredDate`) AS year
FROM `users`
GROUP BY DATE_FORMAT(FROM_UNIXTIME(`userRegistredDate`, '%b'))
登入後複製

此查詢將為您提供用戶總數及其註冊月份和年份。但是,它只會顯示有現有資料的月份。

要包含沒有資料的月份,您可以使用以下方法之一:

方法1 :月份並集

此方法涉及建立所需年份中所有可能月份的並集:

SELECT COUNT(u.userID) AS total, m.month
FROM (
SELECT 'Jan' AS MONTH
UNION SELECT 'Feb' AS MONTH
UNION SELECT 'Mar' AS MONTH
UNION SELECT 'Apr' AS MONTH
UNION SELECT 'May' AS MONTH
UNION SELECT 'Jun' AS MONTH
UNION SELECT 'Jul' AS MONTH
UNION SELECT 'Aug' AS MONTH
UNION SELECT 'Sep' AS MONTH
UNION SELECT 'Oct' AS MONTH
UNION SELECT 'Nov' AS MONTH
UNION SELECT 'Dec' AS MONTH
) AS m
LEFT JOIN users u
ON MONTH(STR_TO_DATE(CONCAT(m.month, ' 2013'),'%M %Y')) = MONTH(u.userRegistredDate)
AND YEAR(u.userRegistredDate) = '2013'
GROUP BY m.month
ORDER BY 1+1;
登入後複製

方法2:日期並集

此方法建立所需年份中所有月份的日期並集:

SELECT COUNT(u.userID) AS total, DATE_FORMAT(merge_date,'%b') AS month, YEAR(m.merge_date) AS year
FROM (
SELECT '2013-01-01' AS merge_date
UNION SELECT '2013-02-01' AS merge_date
UNION SELECT '2013-03-01' AS merge_date
UNION SELECT '2013-04-01' AS merge_date
UNION SELECT '2013-05-01' AS merge_date
UNION SELECT '2013-06-01' AS merge_date
UNION SELECT '2013-07-01' AS merge_date
UNION SELECT '2013-08-01' AS merge_date
UNION SELECT '2013-09-01' AS merge_date
UNION SELECT '2013-10-01' AS merge_date
UNION SELECT '2013-11-01' AS merge_date
UNION SELECT '2013-12-01' AS merge_date
) AS m
LEFT JOIN users u
ON MONTH(m.merge_date) = MONTH(u.userRegistredDate)
AND YEAR(m.merge_date) = YEAR(u.userRegistredDate)
GROUP BY m.merge_date
ORDER BY 1+1;
登入後複製

兩種並集方法都會為所有月份建立佔位符,允許您顯示記錄,即使資料不存在。兩種方法的選擇取決於您的特定要求。

以上是即使特定月份不存在數據,如何在 MySQL 中檢索按月記錄?的詳細內容。更多資訊請關注PHP中文網其他相關文章!

來源:php.cn
本網站聲明
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn
作者最新文章
熱門教學
更多>
最新下載
更多>
網站特效
網站源碼
網站素材
前端模板
關於我們 免責聲明 Sitemap
PHP中文網:公益線上PHP培訓,幫助PHP學習者快速成長!