計算特定時間戳之間的工作時間時,需要考慮週末和指定的工作時間。在 PostgreSQL 中,我們可以利用各種技術來完成此任務。
對於特定時間戳範圍:
以 1 小時為單位,忽略分數。公式如下:
SELECT count(*) AS work_hours FROM generate_series(timestamp '2013-06-24 13:30', timestamp '2013-06-24 15:29' - interval '1h', interval '1h') h WHERE EXTRACT(ISODOW FROM h) < 6 AND h::time >= '08:00' AND h::time <= '14:00';
對於整個表:
-- Table Creation and Data Insertion CREATE TABLE t (t_id int PRIMARY KEY, t_start timestamp, t_end timestamp); INSERT INTO t VALUES (1, '2009-12-03 14:00', '2009-12-04 09:00') , (2, '2009-12-03 15:00', '2009-12-07 08:00') , (3, '2013-06-24 07:00', '2013-06-24 12:00') , (4, '2013-06-24 12:00', '2013-06-24 23:00') , (5, '2013-06-23 13:00', '2013-06-25 11:00') , (6, '2013-06-23 14:01', '2013-06-24 08:59'); -- Main Query SELECT t_id, count(*) AS work_hours FROM ( SELECT t_id, generate_series(t_start, t_end - interval '1h', interval '1h') AS h FROM t ) sub WHERE EXTRACT(ISODOW FROM h) < 6 AND h::time >= '08:00' AND h::time <= '14:00' GROUP BY 1 ORDER BY 1;
要獲得更高的精度,請使用較小的數值時間單位,例如5 分鐘切片。
-- Precision with 5-minute Slices SELECT t_id, count(*) * interval '5 min' AS work_interval FROM ( SELECT t_id, generate_series(t_start, t_end - interval '5 min', interval '5 min') AS h FROM t ) sub WHERE EXTRACT(ISODOW FROM h) < 6 AND h::time >= '08:00' AND h::time <= '14:55' -- 15.00 - interval '5 min' GROUP BY 1 ORDER BY 1;
要獲得精確到微秒的結果,請分別處理開始和結束時間。
Postgres 8.4 :
WITH var AS (SELECT '08:00'::time AS v_start, '15:00'::time AS v_end) SELECT t_id , COALESCE(h.h, '0') -- add / subtract fractions - CASE WHEN EXTRACT(ISODOW FROM t_start) < 6 AND t_start::time > v_start AND t_start::time < v_end THEN t_start - date_trunc('hour', t_start) ELSE '0'::interval END + CASE WHEN EXTRACT(ISODOW FROM t_end) < 6 AND t_end::time > v_start AND t_end::time < v_end THEN t_end - date_trunc('hour', t_end) ELSE '0'::interval END AS work_interval FROM t CROSS JOIN var LEFT JOIN ( -- count full hours, similar to above solutions SELECT t_id, count(*)::int * interval '1h' AS h FROM ( SELECT t_id, v_start, v_end , generate_series(date_trunc('hour', t_start), date_trunc('hour', t_end) - interval '1h', interval '1h') AS h FROM t, var ) sub WHERE EXTRACT(ISODOW FROM h) < 6 AND h::time >= v_start AND h::time <= v_end - interval '1h' GROUP BY 1 ) h USING (t_id)
以上是如何計算 PostgreSQL 中兩個日期之間的工作時間?的詳細內容。更多資訊請關注PHP中文網其他相關文章!