如何使用JSSONUTINE序列化和逐漸化JSON和JSON陣列？

在Unity中使用JsonUtility序列化和反序列化JSON和JSON數組

問題

如何使用C#在Unity中解析和處理JSON數據（單個對象和數組），特別是使用Boomlagoon.JSON、MiniJSON或JsonUtility？

解答

從Unity 5.3.3版本開始，建議使用JsonUtility處理JSON數據，因為它性能高且簡單易用。

1. 單個數據對象的序列化和反序列化：

序列化：

<code class="language-csharp">Player playerInstance = new Player();
playerInstance.playerId = "8484239823";
playerInstance.playerLoc = "Powai";
playerInstance.playerNick = "Random Nick";
string playerToJson = JsonUtility.ToJson(playerInstance);</code>

輸出：

<code class="language-json">{"playerId":"8484239823","playerLoc":"Powai","playerNick":"Random Nick"}</code>

反序列化：

<code class="language-csharp">string jsonString = "{\"playerId\":\"8484239823\",\"playerLoc\":\"Powai\",\"playerNick\":\"Random Nick\"}";
Player player = JsonUtility.FromJson<Player>(jsonString);</code>

2. JSON數組的序列化和反序列化：

為了處理JSON數組，可以使用來自這個GitHub倉庫的輔助類：

輔助類 - JsonHelper.cs

<code class="language-csharp">public static class JsonHelper
{
    public static T[] FromJson<T>(string json)
    {
        Wrapper<T> wrapper = JsonUtility.FromJson<Wrapper<T>>(json);
        return wrapper.Items;
    }

    public static string ToJson<T>(T[] array)
    {
        Wrapper<T> wrapper = new Wrapper<T>();
        wrapper.Items = array;
        return JsonUtility.ToJson(wrapper);
    }

    private class Wrapper<T>
    {
        public T[] Items;
    }
}</code>

序列化：

<code class="language-csharp">Player[] players = new Player[2];
players[0] = new Player { playerId = "8484239823", playerLoc = "Powai", playerNick = "Random Nick" };
players[1] = new Player { playerId = "512343283", playerLoc = "User2", playerNick = "Rand Nick 2" };
string playersToJson = JsonHelper.ToJson(players);</code>

輸出：

<code class="language-json">{"Items":[{"playerId":"8484239823","playerLoc":"Powai","playerNick":"Random Nick"},{"playerId":"512343283","playerLoc":"User2","playerNick":"Rand Nick 2"}]}</code>

反序列化：

<code class="language-csharp">string jsonString = "{\"Items\":[{\"playerId\":\"8484239823\",\"playerLoc\":\"Powai\",\"playerNick\":\"Random Nick\"},{\"playerId\":\"512343283\",\"playerLoc\":\"User2\",\"playerNick\":\"Rand Nick 2\"}]}";
Player[] players = JsonHelper.FromJson<Player>(jsonString);</code>

其他注意事項

• 對於以數字開頭或具有數字屬性的JSON：可以考慮使用Unity Wiki中的SimpleJSON。
• JsonUtility故障排除：確保類不是數組，具有[Serializable]屬性，並且成員未定義為屬性（刪除{ get; set; }）。

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