有多个数组. 怎么计算并获得有多少种组合??数组A、B、C、D里面的个数count不一定都相同。组合顺序是固定的 A[rand] + B[rand] + C[rand] + D[rand] = 不重复字符串怎么获取最大的组合数量、不重复字符串？？ 分享到： ------解决方案--------------------本帖最后由 xuzuning 于 2013-10-11 23:59:51 编辑 数量 = count(A) * count(B) * count(C) * count(D)$a = array('a1', 'a2');$b = array('b1', 'b2');$c = array('c1', 'c2', 'c3');$d = array('d1', 'd2', 'd3');print_r(func($a, $b, $c, $d));function func() { $d = func_get_args(); $r = array_shift($d); while($d) { $t = array(); foreach(array_shift($d) as $x) foreach($r as $y) $t[] = $y . $x; $r = $t; } return $r;}登入後複製Array( [0] => a1b1c1d1 [1] => a2b1c1d1 [2] => a1b2c1d1 [3] => a2b2c1d1 [4] => a1b1c2d1 [5] => a2b1c2d1 [6] => a1b2c2d1 [7] => a2b2c2d1 [8] => a1b1c3d1 [9] => a2b1c3d1 [10] => a1b2c3d1 [11] => a2b2c3d1 [12] => a1b1c1d2 [13] => a2b1c1d2 [14] => a1b2c1d2 [15] => a2b2c1d2 [16] => a1b1c2d2 [17] => a2b1c2d2 [18] => a1b2c2d2 [19] => a2b2c2d2 [20] => a1b1c3d2 [21] => a2b1c3d2 [22] => a1b2c3d2 [23] => a2b2c3d2 [24] => a1b1c1d3 [25] => a2b1c1d3 [26] => a1b2c1d3 [27] => a2b2c1d3 [28] => a1b1c2d3 [29] => a2b1c2d3 [30] => a1b2c2d3 [31] => a2b2c2d3 [32] => a1b1c3d3 [33] => a2b1c3d3 [34] => a1b2c3d3 [35] => a2b2c3d3)
