网上一段简单的preg_match替换 不明
<br />
$string = "Is is the cost of of gasoline going up up"; <br />
$pattern = "/\b([a-z]+) \\1\b/i"; <br />
if(preg_match($pattern, $string,$arr)){<br />
print_r($arr);<br />
echo preg_replace($pattern, '$1', $string);<br />
}<br />
<br />
Array<br />
(<br />
[0] => Is is<br />
[1] => Is<br />
)<br />
Is the cost of gasoline going up<br />
