一个特殊的排序需求的javascript实现代码_javascript技巧-js教程-PHP中文網

一个特殊的排序需求的javascript实现代码_javascript技巧

WBOY

發布： 2016-05-16 18:45:50

原創

916 人瀏覽過

原问题帖在这里：http://topic.csdn.net/u/20081130/09/18d455a6-65e1-4d00-aa8c-d9742654cd8c.html

排序前："Zo","Ad","bC","dad", "bood","bada","Admin","Good","aete","cc","Ko","Beta","Could","AAA" 
<script type="text/javascript"> 
    var t = ["Zo","Ad","bC","dad", "bood","bada","Admin","Good","aete","cc","Ko","Beta","Could","AAA"]; 
    //var t = ['aaa','aaaa']; 
    function sort(arr){ 
        for(var i=0; i<arr.length; i++){ 
            for(var j=0; j<arr.length-i-1; j++){ 
                if(compare(arr[j], arr[j+1])>0){ 
                        var tmp = arr[j]; 
                        arr[j] = arr[j+1]; 
                        arr[j+1] = tmp; 
                } 
                 
            } 
        }     
    } 
     
    function compare(str1, str2){ 
        /** 
        if(str1>str2){ 
            return 1; 
        } 
        return 0; 
        **/ 
        var r = 0; 
        for(var i=0, j=0; i<str1.length&&j<str2.length; i++, j++){ 
            status = 'i=' + i + ' j=' + j; 
            var c1 = str1.charCodeAt(i); 
            var c2 = str2.charCodeAt(j); 
            if(c1>=97) c1-=32; 
            if(c2>=97) c2-=32; 
            if(c1>c2){ 
                return 1; 
            } 
            else if(c1<c2){ 
                return 0; 
            } 
            else if(c1==c2){ 
                if(str1.charCodeAt(i)>str2.charCodeAt(j)){ 
                        return 1; 
                } 
                else if(str1.charCodeAt(i)<str2.charCodeAt(j)){ 
                        return 0; 
                } 
                else if(str1.charCodeAt(i)==str2.charCodeAt(j)){ 
                        continue; 
                } 
            } 
        } 
        if(i!=str1.length){ 
                return 1; 
        } 
        else if(j!=str2.length){ 
                return 0; 
        } 
    } 
    sort(t); 
    alert("排序后：" + t); 
</script>

[Ctrl+A 全选注:如需引入外部Js需刷新才能执行]