数据库中已知一个表数据查询另一个表数据的问题

从tb_xmpcps 可以找到用户名$myrow2['xmpcps_user']，然后再通过用户名去tb_user中找到姓名，两个表嵌套查询还真是第一次做，劳大家指点指点！为什么中说$query2有错误？

   <?php	//查找评分表中相应批次评审状态	$query2=mssql_query("select * from tb_xmpcps where xmpcps_pcid='$xmpc_id'");	$x=1;	while($myrow2=mssql_fetch_array($query2)){	?>  <tr>    <td height="22" align="center" bgcolor="#FFFFFF"><span class="STYLE1"><?php echo $x;?>.</span></td>    <?php		//找到与用户名匹配的评委姓名	 	$query3=mssql_query("select * from tb_user where online_user={$myrow2['xmpcps_user']} limit 1");		$myrow3=mssql_fetch_array($query3);	?>

回复讨论(解决方案)

试试连接表
SELECT B.* FROM tb_xmpcps AS A LEFT OUVER JOIN tb_user AS B ON A.xmpcps_user=B.online_user WHERE A.xmpcps_pcid='$xmpc_id'

$query2=mssql_query("SELECT B.* FROM tb_xmpcps AS A LEFT OUTER JOIN tb_user AS B ON A.xmpcps_user=B.online_user WHERE A.xmpcps_pcid='{$xmpc_id}'");

还是报错啊？为什么？说$query2有错误？劳驾再帮我看看！

   <?php	//查找评分表中相应批次评审状态	$query2=mssql_query("SELECT B.* FROM tb_xmpcps AS A LEFT OUTER JOIN tb_user AS B ON A.xmpcps");	$x=1;	while($myrow2=mssql_fetch_array($query2)){	?>  <tr>    <td height="22" align="center" bgcolor="#FFFFFF"><span class="STYLE1"><?php echo $x;?>.</span></td>	<td height="22" align="center" bgcolor="#FFFFFF" class="STYLE1"><?php echo $myrow2[online_name];?></td>    <td align="center" bgcolor="#FFFFFF" class="STYLE1"><?php echo $myrow2[xmpcps_user];?></td>    <td  align="center" bgcolor="#FFFFFF"><span class="STYLE1"><?php echo $myrow2[xmpcps_state];?></span></td>    </tr>   <?php 		$x++;		}  ?>

echo mssql_get_last_message();
看看都有什么

我最终还是用两个嵌套查询解决了，这样就可以了，还是感谢大家的帮助！

   <?php	//查找评分表中相应批次评审状态	$query2=mssql_query("select * from tb_xmpcps where xmpcps_pcid='$xmpc_id'");	$x=1;	while($myrow2=mssql_fetch_assoc($query2)){	?>  <tr class="STYLE1">    <td height="22" align="center" bgcolor="#FFFFFF"><span class="STYLE1"><?php echo $x;?>.</span></td>    <?php		//找到与用户名匹配的评委姓名	 	$query3=mssql_query("select * from tb_user where online_user='$myrow2[xmpcps_user]'");		$myrow3=mssql_fetch_assoc($query3);	?>