Codeforces Round #135 (Div. 2)-A. k-String_html/css_WEB-ITnose

WBOY
發布: 2016-06-24 11:55:03
原創
924 人瀏覽過

k-String

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

A string is called a k-string if it can be represented as k concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.

You are given a string s, consisting of lowercase English letters and a positive integer k. Your task is to reorder the letters in the string sin such a way that the resulting string is a k-string.

Input

The first input line contains integer k (1?≤?k?≤?1000). The second line contains s, all characters in s are lowercase English letters. The string length s satisfies the inequality 1?≤?|s|?≤?1000, where |s| is the length of string s.

Output

Rearrange the letters in string s in such a way that the result is a k-string. Print the result on a single output line. If there are multiple solutions, print any of them.

If the solution doesn't exist, print "-1" (without quotes).

Sample test(s)

input

2aazz
登入後複製

output

azaz
登入後複製

input

3abcabcabz
登入後複製

output

-1
登入後複製





解题思路:给一个串,问是否能由k个相同的串连接而成。

用STL里的map。扫一遍,分别记录每个字符的个数,在判断所有的字符是否是k的倍数,若不是,则输出-1;否则,遍历依次map,每个字符输出(总个数)/k个,然后重复k次即可。





AC代码:

#include <stdio.h>#include <string.h>#include <iostream>#include <algorithm>#include <vector>#include <queue>#include <set>#include <map>#include <string>#include <math.h>#include <stdlib.h>#include <time.h>using namespace std;#define INF 0x7fffffffmap<char int> m;int main(){    #ifdef sxk        freopen("in.txt","r",stdin);    #endif    int n;    string s;    while(scanf("%d",&n)!=EOF)    {        cin>>s;        int len = s.size();        for(int i=0; i<len i m map int>::iterator it;       int flag = 1;        for(it=m.begin(); it!=m.end(); it++){            if(it->second % n){                flag = 0;                break;            }        }        if(!flag)  printf("-1\n");        else{            for(int j=0; j<n j for it i="1;">second/n; i++)                        printf("%c", it->first);                }            }            printf("\n");        }    }    return 0;}</n></len></char></time.h></stdlib.h></math.h></string></map></set></queue></vector></algorithm></iostream></string.h></stdio.h>
登入後複製


來源:php.cn
本網站聲明
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn
熱門教學
更多>
最新下載
更多>
網站特效
網站源碼
網站素材
前端模板