這是一個計算2000年01月01日起到指定日的天數的函數
(算頭也算尾)日期格式為：YYYY-MM-DD
// 計算從2000年01月01日開始到某日的天數
function cal_start2end($end_day,$start_day)
{
$start_day=ereg_ ","",$start_day);
$end_day=ereg_replace("-","",$end_day);
if($end_day>=$start_day)
{ ////？日期
if(substr($end_day,0,4)==substr($start_day,0,4))
{
if( is_int(substr($end_day,044) )
$leap_day=29; //leap year
else
$leap_day= if(substr($end_day,4,2)== substr($start_day,4,2))
{
// rom_startday=$end_day-$start_day+1;
}
其他
{
// str($end_day,4,2))
{
$endday_from_newyear= substr ($end_day,6,2)+1;
休息；
案例"02":
$endday_from_newyear=substr($end_day,6,2)+31;
休息；
案例中"03": 31;
與的休息；
$endday_from_newyear=substr($end_day ,6,2)+1+$leap_day+31*2;
🎜> $endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31 *2+30;
的休息；
休息；
$endday_from_newyear=substr($end_day,6,2)+1+$ 休息；
+$leap_day+31*2+30*2;
$endday_from_newyear=substr($end_day,6, 休息；
$endday_from_newyear=substr( $end_day,6,2)+1+$leap_day+31*5+30*2;
「10」：
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
案例"11":
地6,2)+1+$leap_day+31*5+30*4;
":
$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,62)+1+$ leap_day+31*5+30*5;
$endday_from_startday=$endday_from_newyear;
} {
// 不同年！
$differ_year=substr($end_day,0,4)-substr($start_day,0,4);
$how_int_4_floor=floor($differ_year/4)+1; // 向下取整
$how_int_4_ceil=ceil($differ_year/4)+1; // 向上取整
if($how_int_4_floor==$how_int_4_ceil)
$how_leap_year=$how_int_4_floor-1;
其他
$how_leap_year=$how_int_4_floor;
$how_noleap_year=$differ_year-$how_leap_year;
$differ_year2day=$how_noleap_year*365+$how_leap_year*366;
if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //閏年
else
$leap_day=28;
if(substr($end_day,4,2)==substr($start_day,4,2))
🎜> $endday_from_startday=$differ_year2day+ （$end _day, 4, 2）；
}
其他
{
// str($end_day,4,2))
{
$endday_from_newyear= substr ($end_day,6,2)+1;
休息；
案例"02":
$endday_from_newyear=substr($end_day,6,2)+1+31;
休息；
+$leap_day+31;
$endday_from_newyear= substr($end_day,6,2)+1+$leap_day+31*2;
05":
$endday_from_newyear=substr($end_day,6,2)+1+ $leap_day+31*2+30;
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30
休息；
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2; 案例"08":
$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,6,2)+1+$leapday+31 休息；
$ endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
案例「10」：
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
案例"11":
地6,2)+1+$leap_day+31*5+30*4;
":
$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,6,2)+1+$endday_from_newyear=substr($end_day,62)+1+$ //leap_day+31*5+30*5;
$endday_from_startday=$endday_from_newyear+$differ_year2day;
} /／不同月結束
return ($endday_from_startday );
} //年末
} //結束$end_day>=$start_day
} //沒有"2011-01-01";
echo "您輸入的是：".$end_day."
n";
$endday_from_startday=cal_start2end($end_day,$start_day);
echo "該日距離$start_day 共".$endday_from_startday." 天";
？ >
時間太少了，那個大蝦可以修改為計算任兩個日期之間的間隔最好！ ！ ！ ！
以上就介紹了2000年諾貝爾文學獎計算2000年01月01日指定希望日的天數，包括2000年諾貝爾文學獎方面的內容，對PHP教程有興趣的朋友有所幫助。
