PHP HTML JavaScript MySQL程式碼如何互相傳值的方法分享

1.PHP 

a.PHP -> HTML & JavaScript 

html程式碼中 

<input type="" readonly="readonly" style=&#39;background-color:#DCDCDC&#39; value=<?php echo $perinfo[ID];?> />

JavaScript程式碼中 
文
程式碼如下: 

<script type="text/javascript"> 
var ability=<?php echo JSON($array);?>; 
</script>

2.HTML 

a. HTML -> PHP (POST方式） 

html程式碼中 

<?php 
$dbcnx = @mysql_connect ( "localhost", "root", "1234" ); 
if (! $dbcnx) { 
echo ("Unable to connect to the " . "database server at this time."); 
exit (); 
} 
if (! @mysql_select_db ( "pms" )) { 
echo ("Unable to locate the joke " . "database at this time."); 
exit (); 
} 
mysql_query ( "SET NAMES &#39;GB2312&#39;" ); 
$q=mysql_query("select * from ability where ALV = 1"); 
while($row=mysql_fetch_array($q)){ 
$array1[] = $row[AName]; 
} 
?>

b. HTML -> JavaScript 


JavaScript程式碼中(可取得，可變更） 
複製程式碼 程式碼如下: 

<form id="form" name="form" method="POST" action="do.php"> 
<input type="hidden" id="count" name="count" value="1"/> 
<input type="submit" name="Submit" value="Search"/> 
</form>

3.Java>

JavaScript程式碼中 

 程式碼如下: 

<?php 
echo $_POST[&#39;count&#39;]; 
?>

html程式碼 
程式碼如下: 

<script type="text/javascript"> 
var te = document.getElementById("count"); 
te.value = 1; 
</script>

g reee

2.html程式碼給php 
程式碼如下: 

<script type="text/javascript"> 
function f(){ 
var id = "2"; 
var a = document.getElementById("a"); 
a.href.replace("(n)", id); 
} 
</script>

　　3.do.php接收到 
程式碼如下: 

<a id="a" href="http://www.php1.cn/"> 
　　b. JavaScript -> PHP