具體程式碼如下:
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Document</title> <style type="text/css"> *{margin:0;padding:0;font-family:"微软雅黑";font-size:14px;-webkit-user-008000--shadow: 3px 3px 10px 0008000-</style> </head> <body> <div class=box> <table id='tab' cellspacing="0" cellpadding="0"> <thead> <tr> <th>姓名</th> <th class='cursor'>年龄</th> <th class='cursor'>武力</th> <th>性别</th> </tr> </thead> <tbody> <tr> <td>令狐冲</td> <td>25</td> <td>99</td> <td>男</td> </tr> <tr class='bg'> <td>令狐冲</td> <td>25</td> <td>99</td> <td>男</td> </tr> </tbody> </table> </div> <script> oTab = document.getElementById('tab' tHead = oTab.tHead; oThs = tHead.rows[0].cells; tBody = oTab.tBodies[0 oRows = data = xhr = xhr.open('get','data.txt',xhr.onreadystatechange = (xhr.readyState===4 && /^2\d{2}$/ val == utils.jsonParse(val);xhr.send( frg =( i = 0;i<data.length;i++ cur = oTr = document.createElement("tr");( key oTd = document.createElement("td"(key==="sex"= cur[key]===0?"男":"女"== ( i = 0;i<oRows.length;i++= i%2===1?"bg": sort(n){ ary = _this = _.flag*=-1 curInn = nexInn = curInnNum = nexInnNum =(isNaN(curInnNum) || isNaN(nexInnNum)){ (curInn.localeCompare(nexInn))* (curInnNum-nexInnNum)* frg =( i = 0;i<ary.length;i++= ( i = 0;i<oThs.length;i++ curTh == i;curTh.flag = -1;(curTh.className==='cursor'= ,</script> </body> </html>
資料data.txt程式碼
[ {"name":"令狐冲","age":24,"score":98,"sex":0}, {"name":"任盈盈","age":22,"score":60,"sex":1}, {"name":"岳灵珊","age":21,"score":88,"sex":1}, {"name":"岳不群","age":26,"score":96,"sex":0}, {"name":"林平之","age":23,"score":90,"sex":0} ]
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