本文主要為大家介紹在ecshop中實現ajax彈跳窗登入功能,程式碼簡單易懂,非常不錯,具有參考借鑒價值,需要的朋友參考下
在上篇文章給大家介紹了使用openSpep方法實現Ecshop登入彈窗框效果,大家點選參考下
下面介紹如何實現AJAX彈窗登入。
在ECSHOP中的user.PHP中有處理使用者登入的請求。
/* 处理 ajax 的登录请求 */ elseif ($action == 'signin') { include_once('includes/cls_json.php'); $json = new JSON; $username = !empty($_POST['username']) ? json_str_iconv(trim($_POST['username'])) : ''; $password = !empty($_POST['password']) ? trim($_POST['password']) : ''; $captcha = !empty($_POST['captcha']) ? json_str_iconv(trim($_POST['captcha'])) : ''; $result = array('error' => 0, 'content' => ''); $captcha = intval($_CFG['captcha']); if (($captcha & CAPTCHA_LOGIN) && (!($captcha & CAPTCHA_LOGIN_FAIL) || (($captcha & CAPTCHA_LOGIN_FAIL) && $_SESSION['login_fail'] > 2)) && gd_version() > 0) { if (empty($captcha)) { $result['error'] = 1; $result['content'] = $_LANG['invalid_captcha']; die($json->encode($result)); } /* 检查验证码 */ include_once('includes/cls_captcha.php'); $validator = new captcha(); $validator->session_word = 'captcha_login'; if (!$validator->check_word($_POST['captcha'])) { $result['error'] = 1; $result['content'] = $_LANG['invalid_captcha']; die($json->encode($result)); } } if ($user->login($username, $password)) { update_user_info(); //更新用户信息 recalculate_price(); // 重新计算购物车中的商品价格 $smarty->assign('user_info', get_user_info()); $ucdata = empty($user->ucdata)? "" : $user->ucdata; $result['ucdata'] = $ucdata; $result['content'] = $smarty->fetch('library/member_info.lbi'); } else { $_SESSION['login_fail']++; if ($_SESSION['login_fail'] > 2) { $smarty->assign('enabled_captcha', 1); $result['html'] = $smarty->fetch('library/member_info.lbi'); } $result['error'] = 1; $result['content'] = $_LANG['login_failure']; } die($json->encode($result)); }
把上面這段程式碼修改一下,刪除需要驗證碼的部分
改成
/* 处理 ajax弹窗登录请求 */ elseif ($action == 'ajax_login') { include_once('includes/cls_json.php'); $json = new JSON; $username = !empty($_POST['username']) ? json_str_iconv(trim($_POST['username'])) : ''; $password = !empty($_POST['password']) ? trim($_POST['password']) : ''; $result = array('error' => 0, 'content' => ''); $captcha = intval($_CFG['captcha']); if ($user->login($username, $password)) { update_user_info(); //更新用户信息 recalculate_price(); // 重新计算购物车中的商品价格 $smarty->assign('user_info', get_user_info()); $ucdata = empty($user->ucdata)? "" : $user->ucdata; $result['ucdata'] = $ucdata; $result['content'] = $smarty->fetch('library/member_info.lbi'); } else { $result['error'] = 1; $result['content'] = $_LANG['login_failure']; } die($json->encode($result)); }
將
// 不需要登录的操作或自己验证是否登录(如ajax处理)的act $not_login_arr = array('login','act_login','register','act_register','act_edit_password','get_password','send_pwd_email','password', 'signin', 'add_tag', 'collect', 'return_to_cart', 'logout', 'email_list', 'validate_email', 'send_hash_mail', 'order_query', 'is_registered', 'check_email','clear_history','qpassword_name', 'get_passwd_question', 'check_answer');
#改成
// 不需要登录的操作或自己验证是否登录(如ajax处理)的act $not_login_arr = array('ajax_login','login','act_login','register','act_register','act_edit_password','get_password','send_pwd_email','password', 'signin', 'add_tag', 'collect', 'return_to_cart', 'logout', 'email_list', 'validate_email', 'send_hash_mail', 'order_query', 'is_registered', 'check_email','clear_history','qpassword_name', 'get_passwd_question', 'check_answer');
//生成层内内容 newp.innerHTML = '<form id="ajax_loginForm">用户名:<br><input type="text" name="username" id="ajax_username"/>密码:<br><input type="password" name="password" id="ajax_password"/><br><br><button type="button" onclick="ajaxLoginSubmit()">登录</button> <button type="button" onclick="closeLoginForm()">关闭</button></form>';
相關文章:有關AJAX的面試問題(附有答案) 詳細為你解析AJAX的使用方法(程式碼貼上) 以上是ECSHOP中實作ajax彈跳窗登入功能的詳細內容。更多資訊請關注PHP中文網其他相關文章!function ajaxLoginSubmit(){
var username = document.getElementById('ajax_username').value;
var password = document.getElementById('ajax_password').value;
Ajax.call('user.php?act=ajax_login','username='+username+'&password='+password,ajaxLoginResponse,'POST','JSON');
}
function ajaxLoginResponse(result){
if(result.error == 0){
alert('登录成功');
}else{
alert('登录失败');
}
return false;
}
上面是我整理給大家的,希望今後對大家有幫助。