用户注册并且设置为己登录状态实现方法,下面实例讲述了如何把表单提交的数据保存到mysql数据库,而没有实现用户注册后自动登录的功能,而实例二就实现了这种做法.
class="brush:php;"><html>
<body>
<?php
$self = $_SERVER['PHP_SELF'];
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$username = $_POST['username'];
$password = $_POST['password'];
if( (!$firstname) or (!$lastname) or (!$username) or (!$password) )
{
$form ="Please enter all new user details...";
$form.="<form action="$self"";
$form.=" method="post">First Name: ";
$form.="<input type="text" name="firstname"";
$form.=" value="$firstname"><br>Last Name: ";
$form.="<input type="text" name="lastname"";
$form.=" value="$lastname"><br>User Name: ";
$form.="<input type="text" name="username"";
$form.=" value="$username"><br>Password: ";
$form.="<input type="text" name="password"";
$form.=" value="$password"><br>";
$form.="<input type="submit" value="Submit">";
$form.="</form>";
echo($form);
}
else
{
$conn = @mysql_connect("localhost","root", "") or die("Could not connect to MySQL");
$db = @mysql_select_db("my_database",$conn) or die("Could not select database");
$sql = "insert into users (first_name,last_name,user_name,password)values ("$firstname","$lastname","$username",password("$password") )";
$result = @mysql_query($sql,$conn)or die("Could not execute query");
if($result){
echo("New user $username added");
}
}
</body></html> 下面个实例更详细,用户注册后并且设置用户的为登录状态,本实现利用了setcookie来保存用户登录信息,先看数据库代码如下:
create table user_info ( user_id char(18), fname char(15), email char(35));
实例文件index.php代码如下:
<?php
$form = "
<form action="index.php" method="post">
<input type="hidden" name="seenform" value="y">
Your first name?:<br>
<input type="text" name="fname" value=""><br>
Your email?:<br>
<input type="text" name="email" value=""><br>
<input type="submit" value="Register!">
</form>
";
if ((! isset ($seenform)) && (! isset ($userid))) :
print $form;
elseif (isset ($seenform) && (! isset ($userid))) :
$uniq_id = uniqid(rand());
@mysql_pconnect("localhost", "root", "") or die("Could not connect to MySQL server!");
@mysql_select_db("user") or die("Could not select user database!");
$query = "INSERT INTO user_info VALUES('$uniq_id', '$fname', '$email')";
$result = mysql_query($query) or die("Could not insert user information!");
setcookie ("userid", $uniq_id, time()+2592000);
print "Congratulations $fname! You are now registered!.";
elseif (isset($userid)) :
@mysql_pconnect("localhost", "root", "") or die("Could not connect to MySQL server!");
@mysql_select_db("user") or die("Could not select user database!");//开源代码phprm.com
$query = "SELECT * FROM user_info WHERE user_id = '$userid'";
$result = mysql_query($query) or die("Could not extract user information!");
$row = mysql_fetch_array($result);
print "Hi ".$row["fname"].",<br>";
print "Your email address is ".$row["email"];
endif;
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