計算菱形的面積和周長的程序，已知對角線是什麼？在C++中，什麼是菱形？

什麼是菱形？

在幾何學中，菱形是四個邊長相同的四邊形。菱形與形狀菱形相似。如果菱形的對角線成直角，那麼它就變成正方形。

菱形的性質是-

• 邊相等
• 對邊平行，對角線相等，是平行四邊形
• 對角線平分直角

下圖是菱形

問題

給定對角線，假設d1 和d2 的任務是找出菱形的面積和周長，其中面積是形狀所佔據的空間，週長是其邊界將覆蓋的空間

要計算長方體的面積和周長，有一個公式-

範例

Input-: d1=6 and d2=12
Output-: The perimeter of rhombus with given diagonals are :26
   The area of rhombus with given diagonals are :36

演算法

Start
Step 1 -> declare function to calculate perimeter of rhombus
   int perimeter(int d1, int d2)
      Declare variable long long int perimeter
      Set perimeter = 2 * sqrt(pow(d1, 2) + pow(d2, 2))
      Print perimeter
Step 2 -> Declare function to calculate area of rhombus
   int area(int d1, int d2)
      Declare long long int area
      Set area = (d1 * d2) / 2
      Print area
Step 3 -> In main()
   Declare variable int d1 = 6, d2 = 12
   Call perimeter(d1, d2)
   Call area(d1, d2)
Stop

範例

#include <iostream>
#include <math.h>
using namespace std;
// program to calculate perimeter of rhombus
int perimeter(int d1, int d2){
   long long int perimeter;
   perimeter = 2 * sqrt(pow(d1, 2) + pow(d2, 2));
   cout<< "The perimeter of rhombus with given diagonals are :"<<perimeter;
}
//program to calculate area of rhombus
int area(int d1, int d2){
   long long int area;
   area = (d1 * d2) / 2;
   cout<<"</p><p>The area of rhombus with given diagonals are :"<< area;
}
int main(){
   int d1 = 6, d2 = 12;
   perimeter(d1, d2);
   area(d1, d2);
   return 0;
}

輸出

The perimeter of rhombus with given diagonals are :26
The area of rhombus with given diagonals are :36

#

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