寫一個C程序，將給定的天數轉換為年、週和天

給定了天數，任務是將給定的天數轉換為年、週和天。

讓我們假設一年中的天數=365

年數=（天數）/365

解釋-：年數將是除以給定天數得到的商與365

週數= (天數% 365) / 7

解釋-：週數將透過收集餘數獲得將天數除以365 ，再除以一週的天數7。

天數= (天數% 365) % 7

說明-：天數是用天數除以365所得的餘數再除以一週的天數7所得的餘數。

範例

Input-:days = 209
Output-: years = 0
   weeks = 29
   days = 6
Input-: days = 1000
Output-: years = 2
   weeks = 38
   days = 4

演算法

Start
Step 1-> declare macro for number of days as const int n=7
Step 2-> Declare function to convert number of days in terms of Years, Weeks and Days
   void find(int total_days)
      declare variables as int year, weeks, days
      Set year = total_days / 365
      Set weeks = (total_days % 365) / n
      Set days = (total_days % 365) % n
      Print year, weeks and days
Step 3-> in main()
   Declare int Total_days = 209
   Call find(Total_days)
Stop

Example

 現場示範

#include <stdio.h>
const int n=7 ;
//find year, week, days
void find(int total_days) {
   int year, weeks, days;
   // assuming its not a leap year
   year = total_days / 365;
   weeks = (total_days % 365) / n;
   days = (total_days % 365) % n;
   printf("years = %d",year);
   printf("</p><p>weeks = %d", weeks);
   printf("</p><p>days = %d ",days);
}
int main() {
   int Total_days = 209;
   find(Total_days);
   return 0;
}

輸出

如果我們執行上述程式碼，它將產生以下輸出

years = 0
weeks = 29
days = 6

#

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