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在兩個單獨的速率限制端點之間同步請求

PHPz
發布: 2024-02-11 10:09:08
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在兩個單獨的速率限制端點之間同步請求

在網路開發中,我們經常會遇到需要在兩個單獨的速率限制端點之間進行同步請求的情況。這時,我們需要找到一種方法來確保請求在合適的時間內發送,並且在達到速率限制時進行等待。在這篇文章中,php小編蘋果將會介紹一個解決方案,幫助您實現這種同步請求的功能,確保資料的準確性和穩定性。讓我們來看看這個解決方案的具體實現吧!

問題內容

我正在使用一些第三方 api,每個 api 都有自己的速率限制。端點1的速率限制為10/s,端點2的速率限制為20/s。

我需要透過端點 1 處理數據,該端點將傳回一個物件數組(2-3000 個物件之間)。然後,我需要取得每個物件並將一些資料傳送到第二個端點,同時遵守第二個端點的速率限制。

我計劃在 go 例程中一次批量發送 10 個請求,確保如果所有 10 個請求都在

最終,我希望能夠限制每個端點一次發出的並發回應數量。特別是如果我必須針對由於伺服器 500 多個回應等原因而導致的失敗請求進行重試。

出於問題的目的,我使用 httpbin 請求來模擬以下場景:

package main

import (
    "bytes"
    "encoding/json"
    "fmt"
    "io"
    "net/http"
    "sync"
    "time"
)

type HttpBinGetRequest struct {
    url string
}

type HttpBinGetResponse struct {
    Uuid       string `json:"uuid"`
    StatusCode int
}

type HttpBinPostRequest struct {
    url  string
    uuid string // Item to post to API
}

type HttpBinPostResponse struct {
    Data       string `json:"data"`
    StatusCode int
}

func main() {

    // Prepare GET requests for 500 requests
    var requests []*HttpBinGetRequest
    for i := 0; i < 500; i++ {
        uri := "https://httpbin.org/uuid"
        request := &HttpBinGetRequest{
            url: uri,
        }
        requests = append(requests, request)
    }

    // Create semaphore and rate limit for the GET endpoint
    getSemaphore := make(chan struct{}, 10)
    getRate := make(chan struct{}, 10)
    for i := 0; i < cap(getRate); i++ {
        getRate <- struct{}{}
    }

    go func() {
        // ticker corresponding to 1/10th of a second
        ticker := time.NewTicker(100 * time.Millisecond)
        defer ticker.Stop()
        for range ticker.C {
            _, ok := <-getRate
            if !ok {
                return
            }
        }
    }()

    // Send our GET requests to obtain a random UUID
    var wg sync.WaitGroup
    for _, request := range requests {
        wg.Add(1)
        // Go func to make request and receive the response
        go func(r *HttpBinGetRequest) {
            defer wg.Done()

            // Check the rate limiter and block if it is empty
            getRate <- struct{}{}

            // Add a token to the semaphore
            getSemaphore <- struct{}{}

            // Remove token when function is complete
            defer func() {
                <-getSemaphore
            }()
            resp, _ := get(r)
            fmt.Printf("%+v\n", resp)
        }(request)
    }
    wg.Wait()

    // I need to add code that obtains the response data from the above for loop
    // then sends the UUID it to its own go routines for a POST request, following a similar pattern above
    // To not violate the rate limit of the second endpoint which is 20 calls per second
    // postSemaphore := make(chan struct{}, 20)
    // postRate := make(chan struct{}, 20)
    // for i := 0; i < cap(postRate); i++ {
    //  postRate <- struct{}{}
    // }
}

func get(hbgr *HttpBinGetRequest) (*HttpBinGetResponse, error) {

    httpResp := &HttpBinGetResponse{}
    client := &http.Client{}
    req, err := http.NewRequest("GET", hbgr.url, nil)
    if err != nil {
        fmt.Println("error making request")
        return httpResp, err
    }

    req.Header = http.Header{
        "accept": {"application/json"},
    }

    resp, err := client.Do(req)
    if err != nil {
        fmt.Println(err)
        fmt.Println("error getting response")
        return httpResp, err
    }

    // Read Response
    body, err := io.ReadAll(resp.Body)
    if err != nil {
        fmt.Println("error reading response body")
        return httpResp, err
    }
    json.Unmarshal(body, &httpResp)
    httpResp.StatusCode = resp.StatusCode
    return httpResp, nil
}

// Method to post data to httpbin
func post(hbr *HttpBinPostRequest) (*HttpBinPostResponse, error) {

    httpResp := &HttpBinPostResponse{}
    client := &http.Client{}
    req, err := http.NewRequest("POST", hbr.url, bytes.NewBuffer([]byte(hbr.uuid)))
    if err != nil {
        fmt.Println("error making request")
        return httpResp, err
    }

    req.Header = http.Header{
        "accept": {"application/json"},
    }

    resp, err := client.Do(req)
    if err != nil {
        fmt.Println("error getting response")
        return httpResp, err
    }

    if resp.StatusCode == 429 {
        fmt.Println(resp.Header.Get("Retry-After"))
    }

    // Read Response
    body, err := io.ReadAll(resp.Body)
    if err != nil {
        fmt.Println("error reading response body")
        return httpResp, err
    }
    json.Unmarshal(body, &httpResp)
    httpResp.StatusCode = resp.StatusCode
    fmt.Printf("%+v", httpResp)
    return httpResp, nil
}
登入後複製

解決方法

這是生產者/消費者模式。您可以使用 chan 來連接它們。

關於速率限制器,我會使用套件 golang.org/x/time/rate

既然我們決定使用chan來連接生產者和消費者,那麼很自然地將失敗的任務發送到同一個chan,以便消費者可以再次嘗試。

我已將邏輯封裝到 scheduler[t] 類型中。請參閱下面的演示。請注意,該演示是匆忙編寫的,僅用於說明想法。尚未經過徹底測試。

package main

import (
    "context"
    "fmt"
    "io"
    "log"
    "math/rand"
    "net/http"
    "net/http/httptest"
    "sort"
    "sync"
    "time"

    "golang.org/x/time/rate"
)

type task[t any] struct {
    param       t
    failedcount int
}

type scheduler[t any] struct {
    name     string
    limit    int
    maxtries int
    wg       sync.waitgroup
    tasks    chan task[t]
    action   func(param t) error
}

// newscheduler creates a scheduler that runs the action with the specified rate limit.
// it will retry the action if the action returns a non-nil error.
func newscheduler[t any](name string, limit, maxtries, chansize int, action func(param t) error) *scheduler[t] {
    return &scheduler[t]{
        name:     name,
        limit:    limit,
        maxtries: maxtries,
        tasks:    make(chan task[t], chansize),
        action:   action,
    }
}

func (s *scheduler[t]) addtask(param t) {
    s.wg.add(1)
    s.tasks <- task[t]{param: param}
}

func (s *scheduler[t]) retrylater(t task[t]) {
    s.wg.add(1)
    s.tasks <- t
}

func (s *scheduler[t]) run() {
    lim := rate.newlimiter(rate.limit(s.limit), 1)
    for t := range s.tasks {
        t := t
        if err := lim.wait(context.background()); err != nil {
            log.fatalf("wait: %s", err)
            return
        }
        go func() {
            defer s.wg.done()
            err := s.action(t.param)
            if err != nil {
                log.printf("task %s, param %v failed: %v", s.name, t.param, err)
                t.failedcount++

                if t.failedcount == s.maxtries {
                    log.printf("task %s, param %v failed with %d tries", s.name, t.param, s.maxtries)
                    return
                }

                s.retrylater(t)
            }
        }()
    }
}

func (s *scheduler[t]) wait() {
    s.wg.wait()
    close(s.tasks)
}

func main() {
    s := &server{}
    ts := httptest.newserver(s)
    defer ts.close()

    schedulerpost := newscheduler("post", 20, 3, 1, func(param string) error {
        return post(fmt.sprintf("%s/%s", ts.url, param))
    })

    go schedulerpost.run()

    schedulerget := newscheduler("get", 10, 3, 1, func(param int) error {
        id, err := get(fmt.sprintf("%s/%d", ts.url, param))
        if err != nil {
            return err
        }

        schedulerpost.addtask(id)
        return nil
    })

    go schedulerget.run()

    for i := 0; i < 100; i++ {
        schedulerget.addtask(i)
    }

    schedulerget.wait()
    schedulerpost.wait()

    s.printstats()
}

func get(url string) (string, error) {
    resp, err := http.get(url)
    if err != nil {
        return "", err
    }
    defer resp.body.close()

    if resp.statuscode != 200 {
        return "", fmt.errorf("unexpected status code: %d", resp.statuscode)
    }

    body, err := io.readall(resp.body)
    if err != nil {
        return "", err
    }

    return string(body), nil
}

func post(url string) error {
    resp, err := http.post(url, "", nil)
    if err != nil {
        return err
    }
    defer resp.body.close()

    if resp.statuscode != 200 {
        return fmt.errorf("unexpected status code: %d", resp.statuscode)
    }

    return nil
}

type server struct {
    gmu  sync.mutex
    gets []int64

    pmu   sync.mutex
    posts []int64
}

func (s *server) servehttp(w http.responsewriter, r *http.request) {
    log.printf("%s: %s", r.method, r.url.path)

    // collect request stats.
    if r.method == http.methodget {
        s.gmu.lock()
        s.gets = append(s.gets, time.now().unixmilli())
        s.gmu.unlock()
    } else {
        s.pmu.lock()
        s.posts = append(s.posts, time.now().unixmilli())
        s.pmu.unlock()
    }

    n := rand.intn(1000)
    // simulate latency.
    time.sleep(time.duration(n) * time.millisecond)

    // simulate errors.
    if n%10 == 0 {
        w.writeheader(http.statusinternalservererror)
        return
    }

    if r.method == http.methodget {
        fmt.fprintf(w, "%s", r.url.path[1:])
        return
    }
}

func (s *server) printstats() {
    log.printf("gets (total: %d):\n", len(s.gets))
    printstats(s.gets)
    log.printf("posts (total: %d):\n", len(s.posts))
    printstats(s.posts)
}

func printstats(ts []int64) {
    sort.slice(ts, func(i, j int) bool {
        return ts[i] < ts[j]
    })

    count := 0
    to := ts[0] + 1000
    for i := 0; i < len(ts); i++ {
        if ts[i] < to {
            count++
        } else {
            fmt.printf("  %d: %d\n", to, count)
            i-- // push back the current item
            count = 0
            to += 1000
        }
    }
    if count > 0 {
        fmt.printf("  %d: %d\n", to, count)
    }
}
登入後複製

輸出如下圖所示:

...
2023/03/25 21:03:30 GETS (total: 112):
  1679749398998: 10
  1679749399998: 10
  1679749400998: 10
  1679749401998: 10
  1679749402998: 10
  1679749403998: 10
  1679749404998: 10
  1679749405998: 10
  1679749406998: 10
  1679749407998: 10
  1679749408998: 10
  1679749409998: 2
2023/03/25 21:03:30 POSTS (total: 111):
  1679749399079: 8
  1679749400079: 8
  1679749401079: 12
  1679749402079: 8
  1679749403079: 10
  1679749404079: 9
  1679749405079: 9
  1679749406079: 8
  1679749407079: 14
  1679749408079: 12
  1679749409079: 9
  1679749410079: 4
登入後複製

以上是在兩個單獨的速率限制端點之間同步請求的詳細內容。更多資訊請關注PHP中文網其他相關文章!

來源:stackoverflow.com
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