為了方便闡述問題我簡化的弄一張多對多的關係表一共3個字段id wid uid 現在希望能查出在一組wid中每個(不重複的)wid 下對應的前5個uid(order by id limit 5) 即最後得出結果為wid1 = [uid, uid, uid, uid ...]wid2 = [uid, uid, uid, uid ...]能不能直接用一條sql取出這樣的結果呢?
假定這張表名字暫定為 demo_table可用下面的語句實現你的需求
SELECT wid, SUBSTRING_INDEX(GROUP_CONCAT(uid ORDER BY id),',',5) AS 'uids' FROM demo_table GROUP BY wid
@deepgoing 的思路沒問題,為了解決uid重複和排序問題,可以先做一次distcint的查詢,如:
SELECT wid, SUBSTRING_INDEX(GROUP_CONCAT(uid ORDER BY id),',',5) AS 'uids' FROM ( SELECT DISTINCT wid, uid FROM demo_table ORDER BY wid, uid ) GROUP BY wid
假定這張表名字暫定為 demo_table
可用下面的語句實現你的需求
@deepgoing 的思路沒問題,為了解決uid重複和排序問題,可以先做一次distcint的查詢,如: