java - 解一道C語言的算法題?求各位大神幫忙

Question

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Answer 1

我想說不考慮演算法選擇要求這就是個2x+b = a 求x的小學數學題，如果對演算法選擇沒要求就是輸入a,b,輸出(a-b)/2 和（a+b）/ 2 .
輸入的時候校驗下a,b是不是同為奇數或偶數以及數字是不是超變量類型的可用範圍，然後自己生成的case也要考慮這個問題

Answer 2

雷雷

Answer 3

透過你提供的材料,用c++編碼如下,望指正!

/*
  if Natalia's number of apples is x  (x>0)
  apples:the number of apple
  extra:the number that Klaudia more tha Natalia
  (apples>extra>0)
  so
  x+extra+x=apples
  x = (apples-extra)/2
*/
#include <iostream>
int main(int argc, char const *argv[]) {
  int apples,extra;   //apples:the number of apple  extra:the number that Klaudia more tha Natalia

  for (size_t i = 0; i < 10; i++) {
        std::cin>>apples>>extra;   //input
        try{
          //To determine whether the input is legal
            if(apples<=0 || extra<=0 || apples<extra || (apples-extra)%2!=0) throw apples;
            int Klaudia,Natalia;
            Natalia = (apples-extra)/2;    //calculate
            Klaudia=Natalia+2;
            std::cout<<Klaudia<<'\n'<<Natalia<<'\n';    //output
      }
        catch(int e){
            //ERROR
            std::cerr << "ERROR! the number of applse is error.\n" << '\n';
        }
  }
  return 0;
}

運行結果