透過PHP返回JSON響應

Question

如何回傳以下回應？

成功時應回傳：

{ status : "ok", data :
  [ { franchisor_no : <franchisor number>
    , franchisor_status : uncollected | active | delivered | returned | exception
  , events_list :
    [ { date: <date>, status : uncollected | active | delivered | returned | exception
       , description: <optional description>
       , code: <optional code, may map to the defined franchisor codes>
       , location: <optional location, such as city or hub>.
       ... raw_event: <the original event as received from the franchisor API. mandatory
... } ] } .... ] }

我正在使用這段程式碼，但是沒有向我的伺服器發送回應。請告訴我這段程式碼中是否有任何錯誤？

<?php
$data = json_decode(file_get_contents("php://input"));

echo json_encode = [
    "status" => "ok",
    "data" => [
        [
            "franchisor_no" => "1210110080",
            "franchisor_status" => "exception",
            "events_list" => [
                [
                    "date" => "30-07-2023",
                    "status" => "exception",
                    "description" => "optional",
                    "code" => "optional",
                    "location" => "optional",
                    "raw_event" => "mandatory"
                ],
            ],
        ],
    ],
];

Answer 1

應該是這樣

echo json_encode([
"status" => "ok",
"data" => [
    [
        "franchisor_no" => "1210110080",
        "franchisor_status" => "exception",
        "events_list" => [
            [
                "date" => "30-07-2023",
                "status" => "exception",
                "description" => "optional",
                "code" => "optional",
                "location" => "optional",
                "raw_event" => "mandatory"
            ],
        ],
    ],
]]);

您沒有呼叫json_encode()函數。您只是在它前面加了一個等號。