合併兩個動態物件數組:將兩個動態物件數組合併為一個
P粉903969231
2023-08-18 14:53:48
<p>我有兩個物件的動態數組,如下所示(這是一個包含n個物件的動態數組):</p>
<pre class="brush:php;toolbar:false;">serverArray = [
{"id":"field1","mandatory":false,"visible":false},
{"id":"field2","mandatory":false,"visible":false},
{"id":"field3","mandatory":false,"visible":false},
{"id":"field4","mandatory":false,"visible":false}
]
localArray = [
{"id":"field1"},
{"id":"field2","mandatory":false},
{"id":"field3","mandatory":true,"visible":false},
{"id":"field4","mandatory":false,"visible":true},
{"id":"field5","mandatory":false,"visible":true},
{"id":"field6","mandatory":true,"visible":false},
]</pre>
<p>我將這兩個數字組合併為具有相同ID的對象,如下所示:</p>
<pre class="brush:php;toolbar:false;">for (let x = 0; x < serverArray.length; x ) {
for (let y = 0; y < localArray.length; y ) {
if (serverArray[x].id == localArray[y].id) { // serverArray[x].id/localArray[y].id = 'field1', 'field2'
for (let key in localArray[y]) { //key = 'id', 'mandatory', etc
serverArray[x][key] = localArray[y].hasOwnProperty(key) ? localArray[y][key] : serverArray[x][key]; //Override with local field attribute value (if present) in final returned response
}
}
}
}</pre>
<p>然而,我還希望在最終的<code>serverArray</code>中包含那些不在<code>serverArray</code>中的ID(即上面範例中的<code>field5</code>中的ID(即上面範例中的<code>field5</ code>,<code>field6</code>),而這些欄位也會失敗上述條件(即<code>serverArray[x].id == localArray[y].id</code>),我希望這些欄位也作為最終<code>serverArray</code>的一部分,即在我的最終<code>serverArray</code>中還應包含以下兩個物件:</p>
<pre class="brush:php;toolbar:false;">{"id":"field5","mandatory":false,"visible":true},
{"id":"field6","mandatory":true,"visible":false},</pre>
<p>有沒有辦法實現這個要求? </p>
在循環遍歷兩個陣列時,您可以建立一個新物件來追蹤合併的欄位。在初始合併之後,您可以再次遍歷localArray,以識別尚未合併到serverArray中的字段,並將它們添加到合併結果中。